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113121301023 = 3212569033447
BaseRepresentation
bin110100101011010001…
…1100001001000011111
3101210222121200111102200
41221112203201020133
53323133023113043
6123544530022543
711113152123303
oct1512643411037
9353877614380
10113121301023
1143a7a030835
1219b10117a53
13a88a0725a3
145691963d03
152e2114c7d3
hex1a568e121f

113121301023 has 6 divisors (see below), whose sum is σ = 163397434824. Its totient is φ = 75414200676.

The previous prime is 113121301021. The next prime is 113121301061. The reversal of 113121301023 is 320103121311.

It is not a de Polignac number, because 113121301023 - 21 = 113121301021 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113121300987 and 113121301005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113121301021) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 6284516715 + ... + 6284516732.

It is an arithmetic number, because the mean of its divisors is an integer number (27232905804).

Almost surely, 2113121301023 is an apocalyptic number.

113121301023 is a deficient number, since it is larger than the sum of its proper divisors (50276133801).

113121301023 is a wasteful number, since it uses less digits than its factorization.

113121301023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12569033453 (or 12569033450 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 113121301023 its reverse (320103121311), we get a palindrome (433224422334).

The spelling of 113121301023 in words is "one hundred thirteen billion, one hundred twenty-one million, three hundred one thousand, twenty-three".

Divisors: 1 3 9 12569033447 37707100341 113121301023