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113121301032000 = 263453443394063
BaseRepresentation
bin11001101110001000011010…
…111101101110110001000000
3112211112021211222002221110000
4121232020122331232301000
5104311334411031011000
61040331112553240000
732553513202525362
oct3156103275566100
9484467758087400
10113121301032000
1133053524403648
121082b7baa03000
134b173a66c5331
141dd1158c8cd32
15d12828253000
hex66e21af6ec40

113121301032000 has 560 divisors, whose sum is σ = 419433796184832. Its totient is φ = 30097509811200.

The previous prime is 113121301031983. The next prime is 113121301032013. The reversal of 113121301032000 is 230103121311.

113121301032000 is a `hidden beast` number, since 1 + 1 + 312 + 1 + 30 + 1 + 0 + 320 + 0 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 286866969 + ... + 287261031.

Almost surely, 2113121301032000 is an apocalyptic number.

113121301032000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113121301032000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (209716898092416).

113121301032000 is an abundant number, since it is smaller than the sum of its proper divisors (306312495152832).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113121301032000 is an equidigital number, since it uses as much as digits as its factorization.

113121301032000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 394545 (or 394516 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 113121301032000 its reverse (230103121311), we get a palindrome (113351404153311).

The spelling of 113121301032000 in words is "one hundred thirteen trillion, one hundred twenty-one billion, three hundred one million, thirty-two thousand".