113121311411333 has 4 divisors (see below), whose sum is σ = 113571993927168. Its totient is φ = 112670628895500.

The previous prime is 113121311411309. The next prime is 113121311411389. The reversal of 113121311411333 is 333114113121311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113121311411333 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113121311411296 and 113121311411305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113121311411033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 225341257541 + ... + 225341258042.

It is an arithmetic number, because the mean of its divisors is an integer number (28392998481792).

Almost surely, 2^{113121311411333} is an apocalyptic number.

It is an amenable number.

113121311411333 is a deficient number, since it is larger than the sum of its proper divisors (450682515835).

113121311411333 is an equidigital number, since it uses as much as digits as its factorization.

113121311411333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 450682515834.

The product of its digits is 1944, while the sum is 29.

Adding to 113121311411333 its reverse (333114113121311), we get a palindrome (446235424532644).

The spelling of 113121311411333 in words is "one hundred thirteen trillion, one hundred twenty-one billion, three hundred eleven million, four hundred eleven thousand, three hundred thirty-three".