Base | Representation |
---|---|
bin | 110100101011010001… |
… | …1100101110001010111 |
3 | 101210222121201110111101 |
4 | 1221112203211301113 |
5 | 3323133024220043 |
6 | 123544530250531 |
7 | 11113152232555 |
oct | 1512643456127 |
9 | 353877643441 |
10 | 113121320023 |
11 | 43a7a044038 |
12 | 19b10126a47 |
13 | a88a07b12a |
14 | 569196abd5 |
15 | 2e2115324d |
hex | 1a568e5c57 |
113121320023 has 4 divisors (see below), whose sum is σ = 113160289968. Its totient is φ = 113082350080.
The previous prime is 113121320021. The next prime is 113121320027. The reversal of 113121320023 is 320023121311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113121320023 - 21 = 113121320021 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113121320021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19480618 + ... + 19486423.
It is an arithmetic number, because the mean of its divisors is an integer number (28290072492).
Almost surely, 2113121320023 is an apocalyptic number.
113121320023 is a deficient number, since it is larger than the sum of its proper divisors (38969945).
113121320023 is an equidigital number, since it uses as much as digits as its factorization.
113121320023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38969944.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 113121320023 its reverse (320023121311), we get a palindrome (433144441334).
The spelling of 113121320023 in words is "one hundred thirteen billion, one hundred twenty-one million, three hundred twenty thousand, twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •