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113121410001 = 3164772288471
BaseRepresentation
bin110100101011010001…
…1111011101111010001
3101210222121220000220220
41221112203323233101
53323133040110001
6123544532223253
711113153056105
oct1512643735721
9353877800826
10113121410001
1143a7a0a56a6
1219b1016ab29
13a88a0b0082
145691991905
152e2116ec36
hex1a568fbbd1

113121410001 has 8 divisors (see below), whose sum is σ = 150837766464. Its totient is φ = 75409663440.

The previous prime is 113121409993. The next prime is 113121410053. The reversal of 113121410001 is 100014121311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 113121410001 - 23 = 113121409993 is a prime.

It is a super-2 number, since 2×1131214100012 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (113121410201) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1094805 + ... + 1193666.

It is an arithmetic number, because the mean of its divisors is an integer number (18854720808).

Almost surely, 2113121410001 is an apocalyptic number.

It is an amenable number.

113121410001 is a deficient number, since it is larger than the sum of its proper divisors (37716356463).

113121410001 is a wasteful number, since it uses less digits than its factorization.

113121410001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2304951.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 113121410001 its reverse (100014121311), we get a palindrome (213135531312).

The spelling of 113121410001 in words is "one hundred thirteen billion, one hundred twenty-one million, four hundred ten thousand, one".

Divisors: 1 3 16477 49431 2288471 6865413 37707136667 113121410001