Base | Representation |
---|---|
bin | 1010010010011101001111… |
… | …0011010000100010011111 |
3 | 1111001102202211101210022110 |
4 | 2210213103303100202133 |
5 | 2440314342243220111 |
6 | 40020430510445103 |
7 | 2245164630132024 |
oct | 244472363204237 |
9 | 44042684353273 |
10 | 11312202320031 |
11 | 3671529334918 |
12 | 1328469803793 |
13 | 6409752a4772 |
14 | 2b172911d54b |
15 | 1493ca2505a6 |
hex | a49d3cd089f |
11312202320031 has 16 divisors (see below), whose sum is σ = 15100556889600. Its totient is φ = 7532662935360.
The previous prime is 11312202319973. The next prime is 11312202320033. The reversal of 11312202320031 is 13002320221311.
11312202320031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11312202320031 - 29 = 11312202319519 is a prime.
It is a super-2 number, since 2×113122023200312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11312202320033) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8543770 + ... + 9778568.
It is an arithmetic number, because the mean of its divisors is an integer number (943784805600).
Almost surely, 211312202320031 is an apocalyptic number.
11312202320031 is a deficient number, since it is larger than the sum of its proper divisors (3788354569569).
11312202320031 is a wasteful number, since it uses less digits than its factorization.
11312202320031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1238366.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 11312202320031 its reverse (13002320221311), we get a palindrome (24314522541342).
The spelling of 11312202320031 in words is "eleven trillion, three hundred twelve billion, two hundred two million, three hundred twenty thousand, thirty-one".
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