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11312211231300 = 22352721375617067
BaseRepresentation
bin1010010010011101010001…
…0101010000001001000100
31111001102210110011112021110
42210213110111100021010
52440314402033400200
640020431425445020
72245165065645300
oct244472425201104
944042713145243
1011312211231300
113671533371001
1213284707a0770
136409770a48c5
142b172a39cd00
151493cae10b50
hexa49d4550244

11312211231300 has 216 divisors, whose sum is σ = 38351587778784. Its totient is φ = 2566774479360.

The previous prime is 11312211231281. The next prime is 11312211231311. The reversal of 11312211231300 is 313211221311.

It is a super-2 number, since 2×113122112313002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 794634 + ... + 4822433.

It is an arithmetic number, because the mean of its divisors is an integer number (177553647124).

Almost surely, 211312211231300 is an apocalyptic number.

11312211231300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11312211231300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19175793889392).

11312211231300 is an abundant number, since it is smaller than the sum of its proper divisors (27039376547484).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11312211231300 is a wasteful number, since it uses less digits than its factorization.

11312211231300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5617235 (or 5617221 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 11312211231300 its reverse (313211221311), we get a palindrome (11625422452611).

The spelling of 11312211231300 in words is "eleven trillion, three hundred twelve billion, two hundred eleven million, two hundred thirty-one thousand, three hundred".