Base | Representation |
---|---|
bin | 110100101011010011… |
… | …0111111110010001111 |
3 | 101210222200101211102212 |
4 | 1221112212333302033 |
5 | 3323133241304012 |
6 | 123545001341035 |
7 | 11113162642166 |
oct | 1512646776217 |
9 | 353880354385 |
10 | 113122213007 |
11 | 43a7a5a3a41 |
12 | 19b1049777b |
13 | a88a30171b |
14 | 5691b203dd |
15 | 2e2127cb22 |
hex | 1a569bfc8f |
113122213007 has 8 divisors (see below), whose sum is σ = 115170685056. Its totient is φ = 111090063832.
The previous prime is 113122212961. The next prime is 113122213067. The reversal of 113122213007 is 700312221311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 113122213007 - 26 = 113122212943 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113122213067) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4066733 + ... + 4094454.
It is an arithmetic number, because the mean of its divisors is an integer number (14396335632).
Almost surely, 2113122213007 is an apocalyptic number.
113122213007 is a deficient number, since it is larger than the sum of its proper divisors (2048472049).
113122213007 is an equidigital number, since it uses as much as digits as its factorization.
113122213007 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8161437.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 113122213007 its reverse (700312221311), we get a palindrome (813434434318).
The spelling of 113122213007 in words is "one hundred thirteen billion, one hundred twenty-two million, two hundred thirteen thousand, seven".
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