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11312244433 = 71616034919
BaseRepresentation
bin10101000100100001…
…10010011011010001
31002012100222120002001
422202100302123101
5141131413310213
65110300354001
7550220330320
oct124220623321
932170876061
1011312244433
114885515746
122238545901
1310b3821779
147945500b7
154631bb1dd
hex2a24326d1

11312244433 has 4 divisors (see below), whose sum is σ = 12928279360. Its totient is φ = 9696209508.

The previous prime is 11312244421. The next prime is 11312244439. The reversal of 11312244433 is 33444221311.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11312244433 is a prime.

It is a super-2 number, since 2×113122444332 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11312244439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 808017453 + ... + 808017466.

It is an arithmetic number, because the mean of its divisors is an integer number (3232069840).

Almost surely, 211312244433 is an apocalyptic number.

It is an amenable number.

11312244433 is a deficient number, since it is larger than the sum of its proper divisors (1616034927).

11312244433 is an equidigital number, since it uses as much as digits as its factorization.

11312244433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1616034926.

The product of its digits is 6912, while the sum is 28.

Adding to 11312244433 its reverse (33444221311), we get a palindrome (44756465744).

The spelling of 11312244433 in words is "eleven billion, three hundred twelve million, two hundred forty-four thousand, four hundred thirty-three".

Divisors: 1 7 1616034919 11312244433