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11312255505151 = 16523368462447
BaseRepresentation
bin1010010010011101011011…
…1110001001001011111111
31111001102220112110212120201
42210213112332021023333
52440314444402131101
640020440050424331
72245166144163466
oct244472676111377
944042815425521
1011312255505151
113671556360667
1213284835920a7
13640983306853
142b17322059dd
151493cec58e01
hexa49d6f892ff

11312255505151 has 4 divisors (see below), whose sum is σ = 11312324132832. Its totient is φ = 11312186877472.

The previous prime is 11312255505143. The next prime is 11312255505223. The reversal of 11312255505151 is 15150555221311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11312255505151 - 23 = 11312255505143 is a prime.

It is a super-2 number, since 2×113122555051512 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11312255505151.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11312255515151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34065991 + ... + 34396456.

It is an arithmetic number, because the mean of its divisors is an integer number (2828081033208).

Almost surely, 211312255505151 is an apocalyptic number.

11312255505151 is a deficient number, since it is larger than the sum of its proper divisors (68627681).

11312255505151 is an equidigital number, since it uses as much as digits as its factorization.

11312255505151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 68627680.

The product of its (nonzero) digits is 37500, while the sum is 37.

The spelling of 11312255505151 in words is "eleven trillion, three hundred twelve billion, two hundred fifty-five million, five hundred five thousand, one hundred fifty-one".

Divisors: 1 165233 68462447 11312255505151