Search a number
-
+
11312255505335 = 517655112814717
BaseRepresentation
bin1010010010011101011011…
…1110001001001110110111
31111001102220112110212211112
42210213112332021032313
52440314444402132320
640020440050425235
72245166144164151
oct244472676111667
944042815425745
1011312255505335
113671556360814
12132848359221b
13640983306965
142b1732205ad1
151493cec58ec5
hexa49d6f893b7

11312255505335 has 8 divisors (see below), whose sum is σ = 13574784554016. Its totient is φ = 9049752439200.

The previous prime is 11312255505223. The next prime is 11312255505337. The reversal of 11312255505335 is 53350555221311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-11312255505335 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11312255505292 and 11312255505301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11312255505337) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5524604 + ... + 7290113.

It is an arithmetic number, because the mean of its divisors is an integer number (1696848069252).

Almost surely, 211312255505335 is an apocalyptic number.

11312255505335 is a deficient number, since it is larger than the sum of its proper divisors (2262529048681).

11312255505335 is a wasteful number, since it uses less digits than its factorization.

11312255505335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12991273.

The product of its (nonzero) digits is 337500, while the sum is 41.

The spelling of 11312255505335 in words is "eleven trillion, three hundred twelve billion, two hundred fifty-five million, five hundred five thousand, three hundred thirty-five".

Divisors: 1 5 176551 882755 12814717 64073585 2262451101067 11312255505335