1131230414133 has 12 divisors (see below), whose sum is σ = 1634266516428. Its totient is φ = 754030365120.

The previous prime is 1131230414113. The next prime is 1131230414159. The reversal of 1131230414133 is 3314140321311.

1131230414133 is a `hidden beast` number, since 1 + 1 + 3 + 1 + 230 + 414 + 13 + 3 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 187210251684 + 944020162449 = 432678^2 + 971607^2 .

It is not a de Polignac number, because 1131230414133 - 2⁵ = 1131230414101 is a prime.

It is a super-2 number, since 2×1131230414133² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1131230414097 and 1131230414106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131230414113) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 10212210 + ... + 10322387.

It is an arithmetic number, because the mean of its divisors is an integer number (136188876369).

Almost surely, 2^{1131230414133} is an apocalyptic number.

It is an amenable number.

1131230414133 is a deficient number, since it is larger than the sum of its proper divisors (503036102295).

1131230414133 is a wasteful number, since it uses less digits than its factorization.

1131230414133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20540724 (or 20540721 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

Adding to 1131230414133 its reverse (3314140321311), we get a palindrome (4445370735444).

The spelling of 1131230414133 in words is "one trillion, one hundred thirty-one billion, two hundred thirty million, four hundred fourteen thousand, one hundred thirty-three".