Base | Representation |
---|---|
bin | 10101000100100010… |
… | …00100111000011111 |
3 | 1002012101010101202222 |
4 | 22202101010320133 |
5 | 141131423220111 |
6 | 5110302135555 |
7 | 550221063605 |
oct | 124221047037 |
9 | 32171111688 |
10 | 11312320031 |
11 | 4885567521 |
12 | 22385815bb |
13 | 10b3849cbc |
14 | 79456d875 |
15 | 4631d37db |
hex | 2a2444e1f |
11312320031 has 4 divisors (see below), whose sum is σ = 11313205392. Its totient is φ = 11311434672.
The previous prime is 11312320027. The next prime is 11312320049. The reversal of 11312320031 is 13002321311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11312320031 - 22 = 11312320027 is a prime.
It is a super-2 number, since 2×113123200312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11312319991 and 11312320009.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11312320091) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 423230 + ... + 449163.
It is an arithmetic number, because the mean of its divisors is an integer number (2828301348).
Almost surely, 211312320031 is an apocalyptic number.
11312320031 is a deficient number, since it is larger than the sum of its proper divisors (885361).
11312320031 is an equidigital number, since it uses as much as digits as its factorization.
11312320031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 885360.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 11312320031 its reverse (13002321311), we get a palindrome (24314641342).
The spelling of 11312320031 in words is "eleven billion, three hundred twelve million, three hundred twenty thousand, thirty-one".
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