Base | Representation |
---|---|
bin | 11001101110001011011101… |
… | …100010010101001011101101 |
3 | 112211112121021110121100100020 |
4 | 121232023131202111023231 |
5 | 104311413102221001240 |
6 | 1040332412524152353 |
7 | 32553660121332135 |
oct | 3156133542251355 |
9 | 484477243540306 |
10 | 113124565406445 |
11 | 3305494a02546a |
12 | 108303700986b9 |
13 | 4b177a6ab2c48 |
14 | 1dd1388633ac5 |
15 | d12969b1a0d0 |
hex | 66e2dd8952ed |
113124565406445 has 16 divisors (see below), whose sum is σ = 181083844311552. Its totient is φ = 60304921663040.
The previous prime is 113124565406389. The next prime is 113124565406459. The reversal of 113124565406445 is 544604565421311.
It is not a de Polignac number, because 113124565406445 - 212 = 113124565402349 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1761209757 + ... + 1761273986.
It is an arithmetic number, because the mean of its divisors is an integer number (11317740269472).
Almost surely, 2113124565406445 is an apocalyptic number.
113124565406445 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
113124565406445 is a deficient number, since it is larger than the sum of its proper divisors (67959278905107).
113124565406445 is a wasteful number, since it uses less digits than its factorization.
113124565406445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3522485892.
The product of its (nonzero) digits is 6912000, while the sum is 51.
The spelling of 113124565406445 in words is "one hundred thirteen trillion, one hundred twenty-four billion, five hundred sixty-five million, four hundred six thousand, four hundred forty-five".
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