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113125435121 = 152374278027
BaseRepresentation
bin110100101011011001…
…1010010011011110001
3101210222220110112100102
41221112303102123301
53323140102410441
6123545154402145
711113232222126
oct1512663223361
9353886415312
10113125435121
1143a813a4846
1219b11590355
13a88ab8c1ba
14569231c74d
152e216b769b
hex1a56cd26f1

113125435121 has 4 divisors (see below), whose sum is σ = 113199714672. Its totient is φ = 113051155572.

The previous prime is 113125435061. The next prime is 113125435123. The reversal of 113125435121 is 121534521311.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113125435121 - 214 = 113125418737 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113125435123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37137491 + ... + 37140536.

It is an arithmetic number, because the mean of its divisors is an integer number (28299928668).

Almost surely, 2113125435121 is an apocalyptic number.

It is an amenable number.

113125435121 is a deficient number, since it is larger than the sum of its proper divisors (74279551).

113125435121 is an equidigital number, since it uses as much as digits as its factorization.

113125435121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 74279550.

The product of its digits is 3600, while the sum is 29.

Adding to 113125435121 its reverse (121534521311), we get a palindrome (234659956432).

The spelling of 113125435121 in words is "one hundred thirteen billion, one hundred twenty-five million, four hundred thirty-five thousand, one hundred twenty-one".

Divisors: 1 1523 74278027 113125435121