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11312875045 = 52262575009
BaseRepresentation
bin10101000100100110…
…01100011000100101
31002012102011121010001
422202103030120211
5141132044000140
65110322101301
7550225564663
oct124223143045
932172147101
1011312875045
11488590650a
1222387aa831
1310b39b2804
14794675c33
15463292e9a
hex2a24cc625

11312875045 has 4 divisors (see below), whose sum is σ = 13575450060. Its totient is φ = 9050300032.

The previous prime is 11312875039. The next prime is 11312875087. The reversal of 11312875045 is 54057821311.

It is a Cunningham number, because it is equal to 1063622+1.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4072737124 + 7240137921 = 63818^2 + 85089^2 .

It is a cyclic number.

It is not a de Polignac number, because 11312875045 - 233 = 2722940453 is a prime.

It is a super-2 number, since 2×113128750452 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11312874995 and 11312875013.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1131287500 + ... + 1131287509.

It is an arithmetic number, because the mean of its divisors is an integer number (3393862515).

Almost surely, 211312875045 is an apocalyptic number.

It is an amenable number.

11312875045 is a deficient number, since it is larger than the sum of its proper divisors (2262575015).

11312875045 is an equidigital number, since it uses as much as digits as its factorization.

11312875045 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2262575014.

The product of its (nonzero) digits is 33600, while the sum is 37.

The spelling of 11312875045 in words is "eleven billion, three hundred twelve million, eight hundred seventy-five thousand, forty-five".

Divisors: 1 5 2262575009 11312875045