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113129359045 = 522625871809
BaseRepresentation
bin110100101011100001…
…0010000011011000101
3101211000011211212221221
41221113002100123011
53323142103442140
6123545414440341
711113310454133
oct1512702203305
9354004755857
10113129359045
1143a8363495a
1219b129630b1
13a88b934251
145692a60753
152e21be014a
hex1a570906c5

113129359045 has 4 divisors (see below), whose sum is σ = 135755230860. Its totient is φ = 90503487232.

The previous prime is 113129358989. The next prime is 113129359051. The reversal of 113129359045 is 540953921311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 540953921311 = 2771952902243.

It can be written as a sum of positive squares in 2 ways, for example, as 61606714849 + 51522644196 = 248207^2 + 226986^2 .

It is a cyclic number.

It is not a de Polignac number, because 113129359045 - 213 = 113129350853 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113129358992 and 113129359010.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11312935900 + ... + 11312935909.

It is an arithmetic number, because the mean of its divisors is an integer number (33938807715).

Almost surely, 2113129359045 is an apocalyptic number.

It is an amenable number.

113129359045 is a deficient number, since it is larger than the sum of its proper divisors (22625871815).

113129359045 is an equidigital number, since it uses as much as digits as its factorization.

113129359045 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22625871814.

The product of its (nonzero) digits is 145800, while the sum is 43.

The spelling of 113129359045 in words is "one hundred thirteen billion, one hundred twenty-nine million, three hundred fifty-nine thousand, forty-five".

Divisors: 1 5 22625871809 113129359045