Base | Representation |
---|---|
bin | 110100101011100010… |
… | …0101101001001111111 |
3 | 101211000020001111120220 |
4 | 1221113010231021333 |
5 | 3323142240013043 |
6 | 123545440312423 |
7 | 11113316066604 |
oct | 1512704551177 |
9 | 354006044526 |
10 | 113130001023 |
11 | 43a83a33216 |
12 | 19b13012713 |
13 | a88baca510 |
14 | 5692b8a6ab |
15 | 2e21cba483 |
hex | 1a5712d27f |
113130001023 has 16 divisors (see below), whose sum is σ = 164268286560. Its totient is φ = 68836230144.
The previous prime is 113130001007. The next prime is 113130001037. The reversal of 113130001023 is 320100031311.
It is not a de Polignac number, because 113130001023 - 24 = 113130001007 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113130000993 and 113130001011.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113130001043) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16292986 + ... + 16299927.
It is an arithmetic number, because the mean of its divisors is an integer number (10266767910).
Almost surely, 2113130001023 is an apocalyptic number.
113130001023 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
113130001023 is a deficient number, since it is larger than the sum of its proper divisors (51138285537).
113130001023 is a wasteful number, since it uses less digits than its factorization.
113130001023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32593018.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 113130001023 its reverse (320100031311), we get a palindrome (433230032334).
The spelling of 113130001023 in words is "one hundred thirteen billion, one hundred thirty million, one thousand, twenty-three".
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