11313002400 has 216 divisors, whose sum is σ = 42836320800. Its totient is φ = 2585802240.

The previous prime is 11313002381. The next prime is 11313002419. The reversal of 11313002400 is 420031311.

It is an interprime number because it is at equal distance from previous prime (11313002381) and next prime (11313002419).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 11313002400.

It is an unprimeable number.

It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 69501 + ... + 165699.

It is an arithmetic number, because the mean of its divisors is an integer number (198316300).

Almost surely, 2^11313002400 is an apocalyptic number.

11313002400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11313002400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21418160400).

11313002400 is an abundant number, since it is smaller than the sum of its proper divisors (31523318400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11313002400 is a wasteful number, since it uses less digits than its factorization.

11313002400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 96236 (or 96216 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 11313002400 its reverse (420031311), we get a palindrome (11733033711).

The spelling of 11313002400 in words is "eleven billion, three hundred thirteen million, two thousand, four hundred".