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113130033213 = 337710011071
BaseRepresentation
bin110100101011100010…
…0110101000000111101
3101211000020010010202010
41221113010311000331
53323142242030323
6123545441121433
711113316262501
oct1512704650075
9354006103663
10113130033213
1143a83a5541a
1219b13029279
13a88bb0c072
145692b98301
152e21cc4c93
hex1a5713503d

113130033213 has 4 divisors (see below), whose sum is σ = 150840044288. Its totient is φ = 75420022140.

The previous prime is 113130033199. The next prime is 113130033251. The reversal of 113130033213 is 312330031311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a de Polignac number, because none of the positive numbers 2k-113130033213 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 113130033213.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113130031213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18855005533 + ... + 18855005538.

It is an arithmetic number, because the mean of its divisors is an integer number (37710011072).

Almost surely, 2113130033213 is an apocalyptic number.

It is an amenable number.

113130033213 is a deficient number, since it is larger than the sum of its proper divisors (37710011075).

113130033213 is an equidigital number, since it uses as much as digits as its factorization.

113130033213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37710011074.

The product of its (nonzero) digits is 486, while the sum is 21.

Adding to 113130033213 its reverse (312330031311), we get a palindrome (425460064524).

The spelling of 113130033213 in words is "one hundred thirteen billion, one hundred thirty million, thirty-three thousand, two hundred thirteen".

Divisors: 1 3 37710011071 113130033213