11313010313233 has 4 divisors (see below), whose sum is σ = 11316102148080. Its totient is φ = 11309918478388.

The previous prime is 11313010313219. The next prime is 11313010313273. The reversal of 11313010313233 is 33231301031311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11313010313233 - 2²⁵ = 11312976758801 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11313010313198 and 11313010313207.

It is not an unprimeable number, because it can be changed into a prime (11313010313273) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1545911935 + ... + 1545919252.

It is an arithmetic number, because the mean of its divisors is an integer number (2829025537020).

Almost surely, 2^{11313010313233} is an apocalyptic number.

It is an amenable number.

11313010313233 is a deficient number, since it is larger than the sum of its proper divisors (3091834847).

11313010313233 is an equidigital number, since it uses as much as digits as its factorization.

11313010313233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3091834846.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 11313010313233 its reverse (33231301031311), we get a palindrome (44544311344544).

The spelling of 11313010313233 in words is "eleven trillion, three hundred thirteen billion, ten million, three hundred thirteen thousand, two hundred thirty-three".