113130302000323 has 4 divisors (see below), whose sum is σ = 113762314860840. Its totient is φ = 112498289139808.

The previous prime is 113130302000297. The next prime is 113130302000341. The reversal of 113130302000323 is 323000203031311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113130302000323 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113130302000294 and 113130302000303.

It is not an unprimeable number, because it can be changed into a prime (113130302000363) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 316006429990 + ... + 316006430347.

It is an arithmetic number, because the mean of its divisors is an integer number (28440578715210).

Almost surely, 2^{113130302000323} is an apocalyptic number.

113130302000323 is a deficient number, since it is larger than the sum of its proper divisors (632012860517).

113130302000323 is an equidigital number, since it uses as much as digits as its factorization.

113130302000323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 632012860516.

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 113130302000323 its reverse (323000203031311), we get a palindrome (436130505031634).

The spelling of 113130302000323 in words is "one hundred thirteen trillion, one hundred thirty billion, three hundred two million, three hundred twenty-three", and thus it is an aban number.