Base | Representation |
---|---|
bin | 10101000100100111… |
… | …10010111100101001 |
3 | 1002012102110121210021 |
4 | 22202103302330221 |
5 | 141132114024001 |
6 | 5110325320441 |
7 | 550230123334 |
oct | 124223627451 |
9 | 32172417707 |
10 | 11313033001 |
11 | 4885a04156 |
12 | 2238866121 |
13 | 10b3a3968a |
14 | 7946b761b |
15 | 4632c4ba1 |
hex | 2a24f2f29 |
11313033001 has 8 divisors (see below), whose sum is σ = 11370216704. Its totient is φ = 11255993280.
The previous prime is 11313032989. The next prime is 11313033077. The reversal of 11313033001 is 10033031311.
11313033001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11313033001 - 215 = 11313000233 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11313033601) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 123316 + ... + 194506.
It is an arithmetic number, because the mean of its divisors is an integer number (1421277088).
Almost surely, 211313033001 is an apocalyptic number.
It is an amenable number.
11313033001 is a deficient number, since it is larger than the sum of its proper divisors (57183703).
11313033001 is an equidigital number, since it uses as much as digits as its factorization.
11313033001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 71991.
The product of its (nonzero) digits is 81, while the sum is 16.
Adding to 11313033001 its reverse (10033031311), we get a palindrome (21346064312).
The spelling of 11313033001 in words is "eleven billion, three hundred thirteen million, thirty-three thousand, one".
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