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11313033000 = 23353231271291
BaseRepresentation
bin10101000100100111…
…10010111100101000
31002012102110121210020
422202103302330220
5141132114024000
65110325320440
7550230123333
oct124223627450
932172417706
1011313033000
114885a04155
122238866120
1310b3a39689
147946b761a
154632c4ba0
hex2a24f2f28

11313033000 has 256 divisors, whose sum is σ = 37150064640. Its totient is φ = 2860704000.

The previous prime is 11313032989. The next prime is 11313033077. The reversal of 11313033000 is 33031311.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 8762355 + ... + 8763645.

It is an arithmetic number, because the mean of its divisors is an integer number (145117440).

Almost surely, 211313033000 is an apocalyptic number.

11313033000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11313033000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18575032320).

11313033000 is an abundant number, since it is smaller than the sum of its proper divisors (25837031640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11313033000 is a wasteful number, since it uses less digits than its factorization.

11313033000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1465 (or 1451 counting only the distinct ones).

The product of its (nonzero) digits is 81, while the sum is 15.

Adding to 11313033000 its reverse (33031311), we get a palindrome (11346064311).

The spelling of 11313033000 in words is "eleven billion, three hundred thirteen million, thirty-three thousand".