Base | Representation |
---|---|
bin | 10000011101100110111… |
… | …011101001001100010111 |
3 | 11000011002110202200110102 |
4 | 100131212323221030113 |
5 | 122013402121410403 |
6 | 2223414044044315 |
7 | 144506515321211 |
oct | 20354673511427 |
9 | 4004073680412 |
10 | 1131303310103 |
11 | 3a686825320a |
12 | 16330723369b |
13 | 828b2196b85 |
14 | 3ca80a555b1 |
15 | 1e663c20b88 |
hex | 10766ee9317 |
1131303310103 has 4 divisors (see below), whose sum is σ = 1131306193368. Its totient is φ = 1131300426840.
The previous prime is 1131303310091. The next prime is 1131303310121. The reversal of 1131303310103 is 3010133031311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1131303310103 - 24 = 1131303310087 is a prime.
It is a super-3 number, since 3×11313033101033 (a number of 37 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1131303310133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 738893 + ... + 1675878.
It is an arithmetic number, because the mean of its divisors is an integer number (282826548342).
Almost surely, 21131303310103 is an apocalyptic number.
1131303310103 is a deficient number, since it is larger than the sum of its proper divisors (2883265).
1131303310103 is an equidigital number, since it uses as much as digits as its factorization.
1131303310103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2883264.
The product of its (nonzero) digits is 243, while the sum is 20.
Adding to 1131303310103 its reverse (3010133031311), we get a palindrome (4141436341414).
The spelling of 1131303310103 in words is "one trillion, one hundred thirty-one billion, three hundred three million, three hundred ten thousand, one hundred three".
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