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113131002103 = 7124211301149
BaseRepresentation
bin110100101011100100…
…0100001100011110111
3101211000021221100210221
41221113020201203313
53323143014031403
6123545513555211
711113330436320
oct1512710414367
9354007840727
10113131002103
1143a84557359
1219b13415b07
13a88c08b082
145692d6b447
152e21e16dbd
hex1a572218f7

113131002103 has 8 divisors (see below), whose sum is σ = 129303082400. Its totient is φ = 96961548960.

The previous prime is 113131002007. The next prime is 113131002107. The reversal of 113131002103 is 301200131311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 113131002103 - 221 = 113128904951 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113131002107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 563628 + ... + 737521.

It is an arithmetic number, because the mean of its divisors is an integer number (16162885300).

Almost surely, 2113131002103 is an apocalyptic number.

113131002103 is a deficient number, since it is larger than the sum of its proper divisors (16172080297).

113131002103 is a wasteful number, since it uses less digits than its factorization.

113131002103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1313577.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 113131002103 its reverse (301200131311), we get a palindrome (414331133414).

The spelling of 113131002103 in words is "one hundred thirteen billion, one hundred thirty-one million, two thousand, one hundred three".

Divisors: 1 7 12421 86947 1301149 9108043 16161571729 113131002103