Base | Representation |
---|---|
bin | 110100101011100100… |
… | …0100001100011110111 |
3 | 101211000021221100210221 |
4 | 1221113020201203313 |
5 | 3323143014031403 |
6 | 123545513555211 |
7 | 11113330436320 |
oct | 1512710414367 |
9 | 354007840727 |
10 | 113131002103 |
11 | 43a84557359 |
12 | 19b13415b07 |
13 | a88c08b082 |
14 | 5692d6b447 |
15 | 2e21e16dbd |
hex | 1a572218f7 |
113131002103 has 8 divisors (see below), whose sum is σ = 129303082400. Its totient is φ = 96961548960.
The previous prime is 113131002007. The next prime is 113131002107. The reversal of 113131002103 is 301200131311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 113131002103 - 221 = 113128904951 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113131002107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 563628 + ... + 737521.
It is an arithmetic number, because the mean of its divisors is an integer number (16162885300).
Almost surely, 2113131002103 is an apocalyptic number.
113131002103 is a deficient number, since it is larger than the sum of its proper divisors (16172080297).
113131002103 is a wasteful number, since it uses less digits than its factorization.
113131002103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1313577.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 113131002103 its reverse (301200131311), we get a palindrome (414331133414).
The spelling of 113131002103 in words is "one hundred thirteen billion, one hundred thirty-one million, two thousand, one hundred three".
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