113131003122101 has 4 divisors (see below), whose sum is σ = 113240732515104. Its totient is φ = 113021273729100.

The previous prime is 113131003122089. The next prime is 113131003122121. The reversal of 113131003122101 is 101221300131311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113131003122101 - 2¹⁰ = 113131003121077 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113131003122121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54864694955 + ... + 54864697016.

It is an arithmetic number, because the mean of its divisors is an integer number (28310183128776).

Almost surely, 2^{113131003122101} is an apocalyptic number.

It is an amenable number.

113131003122101 is a deficient number, since it is larger than the sum of its proper divisors (109729393003).

113131003122101 is a wasteful number, since it uses less digits than its factorization.

113131003122101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 109729393002.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 113131003122101 its reverse (101221300131311), we get a palindrome (214352303253412).

The spelling of 113131003122101 in words is "one hundred thirteen trillion, one hundred thirty-one billion, three million, one hundred twenty-two thousand, one hundred one".