11313101303023 has 4 divisors (see below), whose sum is σ = 12183339864808. Its totient is φ = 10442862741240.

The previous prime is 11313101303017. The next prime is 11313101303027. The reversal of 11313101303023 is 32030310131311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11313101303023 is a prime.

It is a super-3 number, since 3×11313101303023³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11313101302985 and 11313101303003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11313101303027) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 435119280873 + ... + 435119280898.

It is an arithmetic number, because the mean of its divisors is an integer number (3045834966202).

Almost surely, 2^{11313101303023} is an apocalyptic number.

11313101303023 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

11313101303023 is a deficient number, since it is larger than the sum of its proper divisors (870238561785).

11313101303023 is an equidigital number, since it uses as much as digits as its factorization.

11313101303023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 870238561784.

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 11313101303023 its reverse (32030310131311), we get a palindrome (43343411434334).

The spelling of 11313101303023 in words is "eleven trillion, three hundred thirteen billion, one hundred one million, three hundred three thousand, twenty-three".