Base | Representation |
---|---|
bin | 11001101110010001011101… |
… | …110110011010000000000010 |
3 | 112211120012220211010010120001 |
4 | 121232101131312122000002 |
5 | 104312014303324320002 |
6 | 1040335400413110214 |
7 | 32554305653104633 |
oct | 3156213566320002 |
9 | 484505824103501 |
10 | 113131013120002 |
11 | 33057658650059 |
12 | 1083166b48836a |
13 | 4b18293857a77 |
14 | 1dd17daaa788a |
15 | d12be5bdda87 |
hex | 66e45dd9a002 |
113131013120002 has 4 divisors (see below), whose sum is σ = 169696519680006. Its totient is φ = 56565506560000.
The previous prime is 113131013119997. The next prime is 113131013120009. The reversal of 113131013120002 is 200021310131311.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 104206101843321 + 8924911276681 = 10208139^2 + 2987459^2 .
It is a super-2 number, since 2×1131310131200022 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (113131013120009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28282753279999 + ... + 28282753280002.
Almost surely, 2113131013120002 is an apocalyptic number.
113131013120002 is a deficient number, since it is larger than the sum of its proper divisors (56565506560004).
113131013120002 is an equidigital number, since it uses as much as digits as its factorization.
113131013120002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 56565506560003.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 113131013120002 its reverse (200021310131311), we get a palindrome (313152323251313).
The spelling of 113131013120002 in words is "one hundred thirteen trillion, one hundred thirty-one billion, thirteen million, one hundred twenty thousand, two".
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