11313102032100 has 432 divisors, whose sum is σ = 39090123072000. Its totient is φ = 2713840588800.

The previous prime is 11313102032093. The next prime is 11313102032101. The reversal of 11313102032100 is 123020131311.

11313102032100 is a `hidden beast` number, since 1 + 1 + 31 + 310 + 2 + 0 + 321 + 0 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (11313102032101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 872985421 + ... + 872998379.

It is an arithmetic number, because the mean of its divisors is an integer number (90486396000).

Almost surely, 2^{11313102032100} is an apocalyptic number.

11313102032100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11313102032100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19545061536000).

11313102032100 is an abundant number, since it is smaller than the sum of its proper divisors (27777021039900).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11313102032100 is a wasteful number, since it uses less digits than its factorization.

11313102032100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13908 (or 13898 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 11313102032100 its reverse (123020131311), we get a palindrome (11436122163411).

The spelling of 11313102032100 in words is "eleven trillion, three hundred thirteen billion, one hundred two million, thirty-two thousand, one hundred".