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1131311330031 = 3377103776677
BaseRepresentation
bin10000011101100111011…
…010001111001011101111
311000011010000212010201210
4100131213122033023233
5122013411200030111
62223414532005503
7144506643433011
oct20354732171357
94004100763653
101131311330031
113a6871830753
12163309a60893
13828b3a443ac
143ca81b421b1
151e6647a70a6
hex1076768f2ef

1131311330031 has 4 divisors (see below), whose sum is σ = 1508415106712. Its totient is φ = 754207553352.

The previous prime is 1131311330003. The next prime is 1131311330033. The reversal of 1131311330031 is 1300331131311.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1131311330031 - 214 = 1131311313647 is a prime.

It is a super-2 number, since 2×11313113300312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131311330033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 188551888336 + ... + 188551888341.

It is an arithmetic number, because the mean of its divisors is an integer number (377103776678).

Almost surely, 21131311330031 is an apocalyptic number.

1131311330031 is a deficient number, since it is larger than the sum of its proper divisors (377103776681).

1131311330031 is an equidigital number, since it uses as much as digits as its factorization.

1131311330031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 377103776680.

The product of its (nonzero) digits is 243, while the sum is 21.

Adding to 1131311330031 its reverse (1300331131311), we get a palindrome (2431642461342).

The spelling of 1131311330031 in words is "one trillion, one hundred thirty-one billion, three hundred eleven million, three hundred thirty thousand, thirty-one".

Divisors: 1 3 377103776677 1131311330031