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11313120133 = 73494630831
BaseRepresentation
bin10101000100101000…
…01000001110000101
31002012102122001022101
422202110020032011
5141132124321013
65110331232101
7550230635350
oct124224101605
932172561271
1011313120133
114885a63667
1222388a8631
1310b3a6a233
147946db297
154632e08dd
hex2a2508385

11313120133 has 8 divisors (see below), whose sum is σ = 12966329600. Its totient is φ = 9669173040.

The previous prime is 11313120121. The next prime is 11313120151. The reversal of 11313120133 is 33102131311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11313120133 - 233 = 2723185541 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11313120133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11313120173) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2312973 + ... + 2317858.

It is an arithmetic number, because the mean of its divisors is an integer number (1620791200).

Almost surely, 211313120133 is an apocalyptic number.

It is an amenable number.

11313120133 is a deficient number, since it is larger than the sum of its proper divisors (1653209467).

11313120133 is an equidigital number, since it uses as much as digits as its factorization.

11313120133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4631187.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 11313120133 its reverse (33102131311), we get a palindrome (44415251444).

The spelling of 11313120133 in words is "eleven billion, three hundred thirteen million, one hundred twenty thousand, one hundred thirty-three".

Divisors: 1 7 349 2443 4630831 32415817 1616160019 11313120133