Base | Representation |
---|---|
bin | 11001101110010001101001… |
… | …101001110000010010010000 |
3 | 112211120020102121201002012200 |
4 | 121232101221221300102100 |
5 | 104312020210022130000 |
6 | 1040335432205123200 |
7 | 32554313606133360 |
oct | 3156215151602220 |
9 | 484506377632180 |
10 | 113131211130000 |
11 | 3305774a3a3988 |
12 | 10831705859500 |
13 | 4b182c589634b |
14 | 1dd18190cc9a0 |
15 | d12c082a3500 |
hex | 66e469a70490 |
113131211130000 has 2400 divisors, whose sum is σ = 499892055336960. Its totient is φ = 23279477760000.
The previous prime is 113131211129971. The next prime is 113131211130031. The reversal of 113131211130000 is 31112131311.
113131211130000 is a `hidden beast` number, since 11 + 31 + 312 + 1 + 11 + 300 + 0 + 0 = 666.
113131211130000 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a polite number, since it can be written in 479 ways as a sum of consecutive naturals, for example, 44875528740 + ... + 44875531260.
Almost surely, 2113131211130000 is an apocalyptic number.
113131211130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 113131211130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (249946027668480).
113131211130000 is an abundant number, since it is smaller than the sum of its proper divisors (386760844206960).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113131211130000 is a wasteful number, since it uses less digits than its factorization.
113131211130000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2767 (or 2743 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 18.
Adding to 113131211130000 its reverse (31112131311), we get a palindrome (113162323261311).
The spelling of 113131211130000 in words is "one hundred thirteen trillion, one hundred thirty-one billion, two hundred eleven million, one hundred thirty thousand".
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