Base | Representation |
---|---|
bin | 10000011101100111100… |
… | …001110111011101110010 |
3 | 11000011010011121202012222 |
4 | 100131213201313131302 |
5 | 122013412203030114 |
6 | 2223415042521042 |
7 | 144506666432636 |
oct | 20354741673562 |
9 | 4004104552188 |
10 | 1131313330034 |
11 | 3a6872977348 |
12 | 16330a666182 |
13 | 828b4294824 |
14 | 3ca82102dc6 |
15 | 1e664a4e98e |
hex | 10767877772 |
1131313330034 has 4 divisors (see below), whose sum is σ = 1696969995054. Its totient is φ = 565656665016.
The previous prime is 1131313330033. The next prime is 1131313330057. The reversal of 1131313330034 is 4300333131311.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1112613588025 + 18699742009 = 1054805^2 + 136747^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1131313329985 and 1131313330012.
It is not an unprimeable number, because it can be changed into a prime (1131313330033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 282828332507 + ... + 282828332510.
Almost surely, 21131313330034 is an apocalyptic number.
1131313330034 is a deficient number, since it is larger than the sum of its proper divisors (565656665020).
1131313330034 is an equidigital number, since it uses as much as digits as its factorization.
1131313330034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 565656665019.
The product of its (nonzero) digits is 2916, while the sum is 26.
Adding to 1131313330034 its reverse (4300333131311), we get a palindrome (5431646461345).
The spelling of 1131313330034 in words is "one trillion, one hundred thirty-one billion, three hundred thirteen million, three hundred thirty thousand, thirty-four".
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