Base | Representation |
---|---|
bin | 110100101011100101… |
… | …0000010110000001010 |
3 | 101211000022200120220100 |
4 | 1221113022002300022 |
5 | 3323143114301302 |
6 | 123545530310230 |
7 | 11113334015052 |
oct | 1512712026012 |
9 | 354008616810 |
10 | 113131400202 |
11 | 43a847a9467 |
12 | 19b13588376 |
13 | a88c19a332 |
14 | 5693032562 |
15 | 2e21e94d1c |
hex | 1a57282c0a |
113131400202 has 12 divisors (see below), whose sum is σ = 245118033810. Its totient is φ = 37710466728.
The previous prime is 113131400197. The next prime is 113131400231. The reversal of 113131400202 is 202004131311.
113131400202 is a `hidden beast` number, since 1 + 1 + 31 + 31 + 400 + 202 = 666.
It can be written as a sum of positive squares in only one way, i.e., 105223033161 + 7908367041 = 324381^2 + 88929^2 .
It is a Harshad number since it is a multiple of its sum of digits (18), and also a Moran number because the ratio is a prime number: 6285077789 = 113131400202 / (1 + 1 + 3 + 1 + 3 + 1 + 4 + 0 + 0 + 2 + 0 + 2).
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 3142538877 + ... + 3142538912.
Almost surely, 2113131400202 is an apocalyptic number.
113131400202 is an abundant number, since it is smaller than the sum of its proper divisors (131986633608).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113131400202 is a wasteful number, since it uses less digits than its factorization.
113131400202 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6285077797 (or 6285077794 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 113131400202 its reverse (202004131311), we get a palindrome (315135531513).
The spelling of 113131400202 in words is "one hundred thirteen billion, one hundred thirty-one million, four hundred thousand, two hundred two".
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