Search a number
-
+
11313140133 = 33771046711
BaseRepresentation
bin10101000100101000…
…01101000110100101
31002012102200001202010
422202110031012211
5141132130441013
65110331504433
7550231050561
oct124224150645
932172601663
1011313140133
114885a77699
1222388b8119
1310b3a76379
147947046a1
154632e67c3
hex2a250d1a5

11313140133 has 4 divisors (see below), whose sum is σ = 15084186848. Its totient is φ = 7542093420.

The previous prime is 11313140131. The next prime is 11313140141. The reversal of 11313140133 is 33104131311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 11313140133 - 21 = 11313140131 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11313140131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1885523353 + ... + 1885523358.

It is an arithmetic number, because the mean of its divisors is an integer number (3771046712).

Almost surely, 211313140133 is an apocalyptic number.

It is an amenable number.

11313140133 is a deficient number, since it is larger than the sum of its proper divisors (3771046715).

11313140133 is an equidigital number, since it uses as much as digits as its factorization.

11313140133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3771046714.

The product of its (nonzero) digits is 324, while the sum is 21.

Adding to 11313140133 its reverse (33104131311), we get a palindrome (44417271444).

The spelling of 11313140133 in words is "eleven billion, three hundred thirteen million, one hundred forty thousand, one hundred thirty-three".

Divisors: 1 3 3771046711 11313140133