11313140214343 has 8 divisors (see below), whose sum is σ = 12344056784640. Its totient is φ = 10282631857080.

The previous prime is 11313140214307. The next prime is 11313140214391. The reversal of 11313140214343 is 34341204131311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11313140214343 - 2³³ = 11304550279751 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11313149214343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 101995305 + ... + 102106162.

It is an arithmetic number, because the mean of its divisors is an integer number (1543007098080).

Almost surely, 2^{11313140214343} is an apocalyptic number.

11313140214343 is a deficient number, since it is larger than the sum of its proper divisors (1030916570297).

11313140214343 is a wasteful number, since it uses less digits than its factorization.

11313140214343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 204106517.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 11313140214343 its reverse (34341204131311), we get a palindrome (45654344345654).

The spelling of 11313140214343 in words is "eleven trillion, three hundred thirteen billion, one hundred forty million, two hundred fourteen thousand, three hundred forty-three".