1131314043332 has 12 divisors (see below), whose sum is σ = 2159781355536. Its totient is φ = 514233656040.

The previous prime is 1131314043329. The next prime is 1131314043341. The reversal of 1131314043332 is 2333404131311.

It is a junction number, because it is equal to n+sod(n) for n = 1131314043295 and 1131314043304.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12855841358 + ... + 12855841445.

It is an arithmetic number, because the mean of its divisors is an integer number (179981779628).

Almost surely, 2^{1131314043332} is an apocalyptic number.

It is an amenable number.

1131314043332 is a deficient number, since it is larger than the sum of its proper divisors (1028467312204).

1131314043332 is a wasteful number, since it uses less digits than its factorization.

1131314043332 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25711682818 (or 25711682816 counting only the distinct ones).

The product of its (nonzero) digits is 7776, while the sum is 29.

Adding to 1131314043332 its reverse (2333404131311), we get a palindrome (3464718174643).

The spelling of 1131314043332 in words is "one trillion, one hundred thirty-one billion, three hundred fourteen million, forty-three thousand, three hundred thirty-two".