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11313201431 = 71616171633
BaseRepresentation
bin10101000100101000…
…11100000100010111
31002012102210011211102
422202110130010113
5141132134421211
65110333100315
7550231424360
oct124224340427
932172704742
1011313201431
114886009754
12223892769b
1310b3a9823c
1479471cb67
15463309a3b
hex2a251c117

11313201431 has 4 divisors (see below), whose sum is σ = 12929373072. Its totient is φ = 9697029792.

The previous prime is 11313201409. The next prime is 11313201439. The reversal of 11313201431 is 13410231311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13410231311 = 54192474669.

It is a cyclic number.

It is not a de Polignac number, because 11313201431 - 226 = 11246092567 is a prime.

It is a super-2 number, since 2×113132014312 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11313201439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 808085810 + ... + 808085823.

It is an arithmetic number, because the mean of its divisors is an integer number (3232343268).

Almost surely, 211313201431 is an apocalyptic number.

11313201431 is a deficient number, since it is larger than the sum of its proper divisors (1616171641).

11313201431 is an equidigital number, since it uses as much as digits as its factorization.

11313201431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1616171640.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 11313201431 its reverse (13410231311), we get a palindrome (24723432742).

The spelling of 11313201431 in words is "eleven billion, three hundred thirteen million, two hundred one thousand, four hundred thirty-one".

Divisors: 1 7 1616171633 11313201431