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1131320161351 = 5919174917989
BaseRepresentation
bin10000011101100111111…
…011111011010001000111
311000011010122110211000201
4100131213323323101013
5122013420430130401
62223415445151331
7144510111464212
oct20354773732107
94004118424021
101131320161351
113a6876812866
121633109bb547
13828b5817023
143ca82da0779
151e66544db01
hex10767efb447

1131320161351 has 4 divisors (see below), whose sum is σ = 1150495079400. Its totient is φ = 1112145243304.

The previous prime is 1131320161327. The next prime is 1131320161397. The reversal of 1131320161351 is 1531610231311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1131320161351 - 25 = 1131320161319 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131320161051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9587458936 + ... + 9587459053.

It is an arithmetic number, because the mean of its divisors is an integer number (287623769850).

Almost surely, 21131320161351 is an apocalyptic number.

1131320161351 is a deficient number, since it is larger than the sum of its proper divisors (19174918049).

1131320161351 is an equidigital number, since it uses as much as digits as its factorization.

1131320161351 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19174918048.

The product of its (nonzero) digits is 1620, while the sum is 28.

Adding to 1131320161351 its reverse (1531610231311), we get a palindrome (2662930392662).

The spelling of 1131320161351 in words is "one trillion, one hundred thirty-one billion, three hundred twenty million, one hundred sixty-one thousand, three hundred fifty-one".

Divisors: 1 59 19174917989 1131320161351