113132121300000 has 864 divisors, whose sum is σ = 450537973599168. Its totient is φ = 26684640000000.

The previous prime is 113132121299867. The next prime is 113132121300041. The reversal of 113132121300000 is 3121231311.

113132121300000 is a `hidden beast` number, since 1 + 131 + 321 + 213 + 0 + 0 + 0 + 0 + 0 = 666.

113132121300000 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 366145575 + ... + 366454425.

It is an arithmetic number, because the mean of its divisors is an integer number (521455987962).

Almost surely, 2^{113132121300000} is an apocalyptic number.

113132121300000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113132121300000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (225268986799584).

113132121300000 is an abundant number, since it is smaller than the sum of its proper divisors (337405852299168).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113132121300000 is a wasteful number, since it uses less digits than its factorization.

113132121300000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 308940 (or 308909 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 113132121300000 its reverse (3121231311), we get a palindrome (113135242531311).

The spelling of 113132121300000 in words is "one hundred thirteen trillion, one hundred thirty-two billion, one hundred twenty-one million, three hundred thousand".