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113132201209 = 816771385117
BaseRepresentation
bin110100101011100110…
…1000110010011111001
3101211000101012021200021
41221113031012103321
53323143320414314
6123545555410441
711113343562256
oct1512715062371
9354011167607
10113132201209
1143a851a6255
1219b138b3a21
13a88c3baac1
1456931a042d
152e220a2324
hex1a573464f9

113132201209 has 4 divisors (see below), whose sum is σ = 113133668004. Its totient is φ = 113130734416.

The previous prime is 113132201191. The next prime is 113132201219. The reversal of 113132201209 is 902102231311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 902102231311 = 8211098784691.

It can be written as a sum of positive squares in 2 ways, for example, as 52933125184 + 60199076025 = 230072^2 + 245355^2 .

It is a cyclic number.

It is not a de Polignac number, because 113132201209 - 29 = 113132200697 is a prime.

It is a super-2 number, since 2×1131322012092 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113132201219) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 610882 + ... + 774235.

It is an arithmetic number, because the mean of its divisors is an integer number (28283417001).

Almost surely, 2113132201209 is an apocalyptic number.

It is an amenable number.

113132201209 is a deficient number, since it is larger than the sum of its proper divisors (1466795).

113132201209 is an equidigital number, since it uses as much as digits as its factorization.

113132201209 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1466794.

The product of its (nonzero) digits is 648, while the sum is 25.

The spelling of 113132201209 in words is "one hundred thirteen billion, one hundred thirty-two million, two hundred one thousand, two hundred nine".

Divisors: 1 81677 1385117 113132201209