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11313233123130 = 2355191092248021
BaseRepresentation
bin1010010010100001000100…
…1111011101011100111010
31111001112102200001000100000
42210220101033131130322
52440324000134420010
640021121052253430
72245232314614621
oct244502117353472
944045380030300
1011313233123130
113671a08187504
1213286b6a71276
13640aaaa08323
142b17c5da86b8
1514943a9b87c0
hexa4a113dd73a

11313233123130 has 192 divisors, whose sum is σ = 32403888316800. Its totient is φ = 2831857770240.

The previous prime is 11313233123119. The next prime is 11313233123131. The reversal of 11313233123130 is 3132133231311.

11313233123130 is a `hidden beast` number, since 1 + 1 + 3 + 1 + 32 + 3 + 312 + 313 + 0 = 666.

11313233123130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 11313233123094 and 11313233123103.

It is not an unprimeable number, because it can be changed into a prime (11313233123131) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 3908520 + ... + 6156540.

It is an arithmetic number, because the mean of its divisors is an integer number (168770251650).

Almost surely, 211313233123130 is an apocalyptic number.

11313233123130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 11313233123130, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16201944158400).

11313233123130 is an abundant number, since it is smaller than the sum of its proper divisors (21090655193670).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11313233123130 is a wasteful number, since it uses less digits than its factorization.

11313233123130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2248171 (or 2248159 counting only the distinct ones).

The product of its (nonzero) digits is 2916, while the sum is 27.

Adding to 11313233123130 its reverse (3132133231311), we get a palindrome (14445366354441).

The spelling of 11313233123130 in words is "eleven trillion, three hundred thirteen billion, two hundred thirty-three million, one hundred twenty-three thousand, one hundred thirty".