Base | Representation |
---|---|
bin | 110100101011101000… |
… | …0001110100010001011 |
3 | 101211000102201221122212 |
4 | 1221113100032202023 |
5 | 3323144023140243 |
6 | 123550025135335 |
7 | 11113353546260 |
oct | 1512720164213 |
9 | 354012657585 |
10 | 113133021323 |
11 | 43a85706433 |
12 | 19b1402a54b |
13 | a88c61718a |
14 | 5693335267 |
15 | 2e221b5318 |
hex | 1a5740e88b |
113133021323 has 4 divisors (see below), whose sum is σ = 129294881520. Its totient is φ = 96971161128.
The previous prime is 113133021301. The next prime is 113133021329. The reversal of 113133021323 is 323120331311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113133021323 - 26 = 113133021259 is a prime.
It is not an unprimeable number, because it can be changed into a prime (113133021329) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8080930088 + ... + 8080930101.
It is an arithmetic number, because the mean of its divisors is an integer number (32323720380).
Almost surely, 2113133021323 is an apocalyptic number.
113133021323 is a deficient number, since it is larger than the sum of its proper divisors (16161860197).
113133021323 is an equidigital number, since it uses as much as digits as its factorization.
113133021323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16161860196.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 113133021323 its reverse (323120331311), we get a palindrome (436253352634).
The spelling of 113133021323 in words is "one hundred thirteen billion, one hundred thirty-three million, twenty-one thousand, three hundred twenty-three".
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