Base | Representation |
---|---|
bin | 11001101110010011011011… |
… | …011011111110110101011011 |
3 | 112211120102100122210221012121 |
4 | 121232103123123332311123 |
5 | 104312033112222402303 |
6 | 1040340345441322111 |
7 | 32554412116244326 |
oct | 3156233333766533 |
9 | 484512318727177 |
10 | 113133120122203 |
11 | 33058539a30a95 |
12 | 10831b59036337 |
13 | 4b1853b227b2c |
14 | 1dd195a8577bd |
15 | d12cbab8a9bd |
hex | 66e4db6fed5b |
113133120122203 has 16 divisors (see below), whose sum is σ = 122257017501696. Its totient is φ = 104382386190720.
The previous prime is 113133120122159. The next prime is 113133120122207. The reversal of 113133120122203 is 302221021331311.
It is a cyclic number.
It is not a de Polignac number, because 113133120122203 - 237 = 112995681168731 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113133120122207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 258204526 + ... + 258642307.
It is an arithmetic number, because the mean of its divisors is an integer number (7641063593856).
Almost surely, 2113133120122203 is an apocalyptic number.
113133120122203 is a deficient number, since it is larger than the sum of its proper divisors (9123897379493).
113133120122203 is a wasteful number, since it uses less digits than its factorization.
113133120122203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 516847194.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 113133120122203 its reverse (302221021331311), we get a palindrome (415354141453514).
The spelling of 113133120122203 in words is "one hundred thirteen trillion, one hundred thirty-three billion, one hundred twenty million, one hundred twenty-two thousand, two hundred three".
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