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11313320333 = 71616188619
BaseRepresentation
bin10101000100101001…
…11001000110001101
31002012110000012221012
422202110321012031
5141132202222313
65110335415005
7550232431130
oct124224710615
932173005835
1011313320333
114886090017
122238984465
1310b3b0a3b3
14794750217
1546332eda8
hex2a253918d

11313320333 has 4 divisors (see below), whose sum is σ = 12929508960. Its totient is φ = 9697131708.

The previous prime is 11313320329. The next prime is 11313320341. The reversal of 11313320333 is 33302331311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11313320333 - 22 = 11313320329 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11313320299 and 11313320308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11313320533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 808094303 + ... + 808094316.

It is an arithmetic number, because the mean of its divisors is an integer number (3232377240).

Almost surely, 211313320333 is an apocalyptic number.

It is an amenable number.

11313320333 is a deficient number, since it is larger than the sum of its proper divisors (1616188627).

11313320333 is an equidigital number, since it uses as much as digits as its factorization.

11313320333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1616188626.

The product of its (nonzero) digits is 1458, while the sum is 23.

Adding to 11313320333 its reverse (33302331311), we get a palindrome (44615651644).

The spelling of 11313320333 in words is "eleven billion, three hundred thirteen million, three hundred twenty thousand, three hundred thirty-three".

Divisors: 1 7 1616188619 11313320333