Base | Representation |
---|---|
bin | 10101000100101001… |
… | …11001001001101011 |
3 | 1002012110000020020102 |
4 | 22202110321021223 |
5 | 141132202224210 |
6 | 5110335420015 |
7 | 550232431565 |
oct | 124224711153 |
9 | 32173006212 |
10 | 11313320555 |
11 | 48860901a9 |
12 | 223898460b |
13 | 10b3b0a524 |
14 | 794750335 |
15 | 46332eea5 |
hex | 2a253926b |
11313320555 has 4 divisors (see below), whose sum is σ = 13575984672. Its totient is φ = 9050656440.
The previous prime is 11313320539. The next prime is 11313320581. The reversal of 11313320555 is 55502331311.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 11313320555 - 24 = 11313320539 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1131332051 + ... + 1131332060.
It is an arithmetic number, because the mean of its divisors is an integer number (3393996168).
Almost surely, 211313320555 is an apocalyptic number.
11313320555 is a deficient number, since it is larger than the sum of its proper divisors (2262664117).
11313320555 is an equidigital number, since it uses as much as digits as its factorization.
11313320555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2262664116.
The product of its (nonzero) digits is 6750, while the sum is 29.
Adding to 11313320555 its reverse (55502331311), we get a palindrome (66815651866).
The spelling of 11313320555 in words is "eleven billion, three hundred thirteen million, three hundred twenty thousand, five hundred fifty-five".
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