113133403511241 has 4 divisors (see below), whose sum is σ = 150844538014992. Its totient is φ = 75422269007492.

The previous prime is 113133403511239. The next prime is 113133403511257. The reversal of 113133403511241 is 142115304331311.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113133403511241 - 2¹ = 113133403511239 is a prime.

It is a super-2 number, since 2×113133403511241² (a number of 29 digits) contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (113133403511221) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18855567251871 + ... + 18855567251876.

It is an arithmetic number, because the mean of its divisors is an integer number (37711134503748).

Almost surely, 2^{113133403511241} is an apocalyptic number.

It is an amenable number.

113133403511241 is a deficient number, since it is larger than the sum of its proper divisors (37711134503751).

113133403511241 is an equidigital number, since it uses as much as digits as its factorization.

113133403511241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37711134503750.

The product of its (nonzero) digits is 12960, while the sum is 33.

Adding to 113133403511241 its reverse (142115304331311), we get a palindrome (255248707842552).

The spelling of 113133403511241 in words is "one hundred thirteen trillion, one hundred thirty-three billion, four hundred three million, five hundred eleven thousand, two hundred forty-one".