11313400151 has 4 divisors (see below), whose sum is σ = 11313621672. Its totient is φ = 11313178632.

The previous prime is 11313400117. The next prime is 11313400177. The reversal of 11313400151 is 15100431311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15100431311 = 7 ⋅2157204473.

It is a cyclic number.

It is not a de Polignac number, because 11313400151 - 2¹⁰ = 11313399127 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11313400181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9041 + ... + 150693.

It is an arithmetic number, because the mean of its divisors is an integer number (2828405418).

Almost surely, 2^11313400151 is an apocalyptic number.

11313400151 is a deficient number, since it is larger than the sum of its proper divisors (221521).

11313400151 is an equidigital number, since it uses as much as digits as its factorization.

11313400151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 221520.

The product of its (nonzero) digits is 180, while the sum is 20.

Adding to 11313400151 its reverse (15100431311), we get a palindrome (26413831462).

The spelling of 11313400151 in words is "eleven billion, three hundred thirteen million, four hundred thousand, one hundred fifty-one".