1131340543303 has 8 divisors (see below), whose sum is σ = 1133516625696. Its totient is φ = 1129164775200.

The previous prime is 1131340543271. The next prime is 1131340543331. The reversal of 1131340543303 is 3033450431311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1131340543303 - 2⁵ = 1131340543271 is a prime.

It is a super-2 number, since 2×1131340543303² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131340540303) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7903950 + ... + 8045812.

It is an arithmetic number, because the mean of its divisors is an integer number (141689578212).

Almost surely, 2^{1131340543303} is an apocalyptic number.

1131340543303 is a deficient number, since it is larger than the sum of its proper divisors (2176082393).

1131340543303 is a wasteful number, since it uses less digits than its factorization.

1131340543303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 157145.

The product of its (nonzero) digits is 19440, while the sum is 31.

Adding to 1131340543303 its reverse (3033450431311), we get a palindrome (4164790974614).

The spelling of 1131340543303 in words is "one trillion, one hundred thirty-one billion, three hundred forty million, five hundred forty-three thousand, three hundred three".